Power output of a star
Stars emit massive amounts of energy per second and
so the power of a star is enormous. We assume that a star behaves as a perfectly 'black body' in
other words it is a perfect radiator of radiation at its surface temperature.
The Stefan-
Boltzmann law states that the power emitted by a black body of surface area A and with a surface
temperature T (K) is given by the equation:
Power =
sAT
4 where
s is a constant
(5.7x10
-8 Wm
-2K
-4).
(Note: we are assuming here that the
temperature of the surroundings (deep space) has a temperature of 0 K)
If we assume
that a star is roughly spherical then A = 4
pr
2 for a
star of radius r.
The power of a star is therefore 4
psr
2T
4 = 7.16x10
-7r
2T
4.
Consider our
Sun. It is a star of surface temperature 6000 K, and a radius 6.96x10
8 m.
Using the preceding equation we can calculate its power output:
Power output
of the Sun = 7.16x10
-7r
2T
4 = 7.16x10
-7x[6.96x10
8]2x[6000
4]
= 7.16x10
-7x 4.84x10
17x1.296x10
15
= 4.5x10
26 W
An alternative way of finding out the
power output of the Sun is to use the solar constant.
(See: 16-19/Thermal
physics/Transfer of heat/Text/Solar constant)It is interesting to compare this power
output with that of Canopus (
a Carinae). Canopus has a surface temperature of 7500 K
and a radius of 2x10
11 m. Using these figures it is possible to calculate its
power output as being in the region of 9x10
31 W, about 200 000 times greater than that
of the Sun!