When any object rises or falls through a fluid it will experience a viscous
drag, whether it is a parachutist or spacecraft falling through air, a stone falling through water or
a bubble rising through fizzy lemonade. The mathematics of the viscous drag on irregular
shapes is difficult; we will consider here only the case of a falling sphere. The formula was first
suggested by Stokes and is therefore known as Stokes' law.
Consider a sphere falling through a viscous fluid. As the sphere falls so its velocity increases until it reaches a velocity known as the terminal velocity. At this velocity the frictional drag due to viscous forces is just balanced by the gravitational force and the velocity is constant (shown by Figure 2).
At this speed:
Viscous drag = 6πηrv = Weight = mg
The following formula can be proved (see dimensional proof)
where v is the terminal velocity of the
From the formula it can be seen that the frictional drag is smaller for large spheres than for small ones, and therefore the terminal velocity of a large sphere is greater than that for a small sphere of the same material.
Stokes' law is important in Millikan's experiment for the measurement of the charge on an electron, and it also explains why large raindrops hurt much more than small ones when they fall on you - it's not just that they are heavier, they are actually falling faster.
People falling through the atmosphere will also eventually reach their terminal velocity. For low-level air (below about 3000 m) this is around 200 km/hour flat out and just over 320 km/hour head down. However at high altitudes around 30 000m this can reach almost 1000 km/hour!
Figure 3 shows how the velocity of an object will increase with time as it falls through a viscous fluid.
It is interesting to consider the effect of various shapes of objects falling through a fluid. These can be made from plasticene.
See the section on subsonic, supersonic and hypersonic vehicles and the shape of the bulbous bow on a nuclear powered submarine.