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Object projected vertically upwards 1. Maximum height reached (H) = ˝ gt2 = u2/2g 2. At any other height except the maximum: h = ut +˝gt2space v2 = u2 +2gh spa where g = - 9.8 ms-2 |
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Object projected horizontally The horizontal distance travelled (s) = horizontal velocity x time = vxt = ut The vertical distance travelled (h) = uyt + ˝ (gt2) = ˝ (gt2) since uy = 0 Velocity after a time t: space v = (vx2 + vy2)1/2 Direction of motion after time t: space tanq = vy/vx Equation for the path: spaceh = ˝ (gt2) = ˝ (gs2/u2) = s2( ˝ )(g/u2) |