Spark image

Circular Motion

As you know according to Newton's First law a body remains at rest or travels in a straight line unless an unbalanced force acts on it. So to make a body travel in a curve a force must act to pull the body away from its straight line. This curved path could be a parabola, as in the case of a projectile moving in a gravitational field, a hyperbola, as for an alpha particle near a nucleus, an ellipse, planets in motion round the Sun or a circle, as in a stone whirled round your head on a string.

In a circle the radius is always at right angles to the motion and since the string is the radius of the circle the force that acts on the stone must be along the string - at right angles to the path of the stone.

Examples of "everyday" circular motion are given below together with the force that makes the paths circular.

Example Force
Centrifuge reaction at walls
Aircraft banking component of lift on the wings
Electron orbits electrostatic force
Car cornering friction between road and tyres
Planetary orbits (almost!) gravitation
Car cornering on banked track component of gravity
Rotating liquid gravity
Car tyres rotating tension in the tyre
A CD tension in the CD
 

Centripetal force

The force that pulls an object out of a straight line path into a circular orbit is called the centripetal force. (The word means centre seeking). It is the force on the orbiting object. Thinking about the stone being whirled round on the end of a string. From Newton's Third Law states we know that if a force acts on the stone then there must be an equal and opposite force acting on another body - this will be a force on the hand holding the string and this force is known as the centrifugal force (the word means fleeing from the centre). If you like to put it this way the centrifugal force is the reaction of the centripetal force on the pivot. As far as the orbingt object (in this case the stone) is concerned the centrifugal force is a fictitious force – it does NOT act on the stone.


If you remove the centripetal force, in the example of the stone and string by cutting the string, the stone will move off along a straight line in the direction it was moving at the instant the string was cut along the tangent to the circle (ignoring gravity for a moment) and not along a radius.

The photograph shows a sparkler being spun in a vertical circle. It celarly shows that the small particles of burning metal move in straight lines when the become detatched from the sparkler.

Angular displacement is expressed in radians. A radian is defined as the angle subtended at the centre of the circle by an arc of length equal to the radius of that circle. In one complete circle there are 2π radians and so one radian equals just over 57o.

 

To watch a video of the spinning sparkler please click on the following link: Spinning sparklers

Angular velocity

When an object is travelling in a circle it has an instantaneous linear velocity but it also has an angular velocity (w). This is defined as the rate of change of angle with time and is usually expressed in radians per second.

For a rotating body that is rigid such as a CD or a wheel the angular velocity is the same at all points on the body while the linear gets greater as the distance from the centre gets larger. However if the body is not rigid like soup in a bowl that is being spun round the angular velocity changes. A fun experiment to demonstrate the forces in rotating objects and to simulate what happens to a spinning car tyre is to rotate a jelly on a turntable and see when it begins to break apart.

If we take T to be the time for one complete rotation - called the period of the motion then

T = circumference/linear velocity =2πr/v = total angle/angular velocity = 2π/ω

Since T is the period (the time to make one complete rotation) the number of rotations per second (n) is 1/T and is the frequency of the motion.

Linear velocity and angular velocity are therefore connected by the formula:

Linear velocity and angular velocity:          v = rω

When an object moves in a circle the linear velocity must be constantly changing as the direction of motion is changing - there must therefore be an acceleration - the centripetal acceleration, and therefore a force - the centripetal force. Both the centripetal acceleration and the centripetal force are directed towards the centre of the circle.

Example problems
1. A stirrer in a food mixer rotates so that the end of it is moving round once in 0.07 s. If the length of this stirrer arm is 9.0 cm calculate:
(a) the linear velocity at the end of the arm
(b) the linear velocity half way along the arm
(c) the angular velocity of the arm
(d) the number of revolutions per second (the frequency)

(a) Linear velocity = Circumference/time = 2π0.08/0.07 = 8.08 ms-1
(b) Linear velocity = Circumference/time = 2π0.04/0.07 = 4.04 ms-1
(c) Angular velocity = Total angle/time = 2π/0.07 = 89.8 radians per second
(d) Number of revolutions per second (n) = 1/T = 1/0.07 = 14.3

2. A helicopter's rotor blades rotate so that the speed of the tip is roughly the same for all helicopters regardless of the length of the blades.
Calculate this speed for the Westland Lynx if the rotor blades are 6.40 m long and they rotate with a frequency of 4.974 Hz.

Time for one rotation = 1/f = 0.202 s
Therefore speed of the end of the blade = 2π x 6.4/0.202 = 200 ms-1

The rotating jelly

A very good way to simulate the break up of car tyres is to make a jelly and put it on a rotating table. As the rate of rotation of the table is increased so the jelly spreads out and flattens. The forces within the jelly keep it together but a point will be reached where these forces are no longer great enough, it can no longer stay in one piece and flies apart, just like car tyres on a motorway.



Student Investigation
Set up a candle inside a vertical glass tube with a diameter of about 5 cm near to the edge of a horizontal table. Rotate the table using a variable speed motor and observe the effect on the flame. A table of 30 cm radius rotating at 1 Hz should show the effects well.
 

A VERSION IN WORD IS AVAILABLE ON THE SCHOOLPHYSICS USB
 
 
 
 
© Keith Gibbs 2020